x^2+36x+323=0

Solution for x^2+36x+323=0 equation:

x^2+36x+323=0

a = 1; b = 36; c = +323;
Δ = b2-4ac
Δ = 362-4·1·323
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-2}{2*1}=\frac{-38}{2}
=-19
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+2}{2*1}=\frac{-34}{2}
=-17
$